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2x^2=-34x
We move all terms to the left:
2x^2-(-34x)=0
We get rid of parentheses
2x^2+34x=0
a = 2; b = 34; c = 0;
Δ = b2-4ac
Δ = 342-4·2·0
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-34}{2*2}=\frac{-68}{4} =-17 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+34}{2*2}=\frac{0}{4} =0 $
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